What is the integral from 1 to infinity of x^{-2/3} ?

The integral from 1 to infinity of x^{-2/3} is diverges

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integral from 1 to infinity of x^{-2/3}

\int_{1}^{\infty} x^{- \frac{2}{3}} d x

diverges

Solution steps

\int_{1}^{\infty} x^{- \frac{2}{3}} d x

Compute the indefinite integral:

\int x^{- \frac{2}{3}} d x = 3 x^{\frac{1}{3}} + C

Compute the boundaries:

\int_{1}^{\infty} x^{- \frac{2}{3}} d x =

diverges

= diverges

\int (x^{2} + 1) cos (x) d x

x \to 2 lim (x^{2} - \frac{4}{x - 2})

\int x ln (1 + x^{2}) d x

\frac{d y}{d x} = (\frac{y}{x})

\frac{d}{d x} (x^{4} sin (x) sin (3 x))

What is the integral from 1 to infinity of x^{-2/3} ?
The integral from 1 to infinity of x^{-2/3} is diverges