What is the solution for (4x-y)dx+(6y-x)dy=0 ?

The solution for (4x-y)dx+(6y-x)dy=0 is y=(x+sqrt(-23x^2+c_{1)})/6 ,y=(x-sqrt(-23x^2+c_{1)})/6

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(4x-y)dx+(6y-x)dy=0

(4 x - y) d x + (6 y - x) d y = 0

y = \frac{x + - 23 x ^{2} + c _{1}}{6}, y = \frac{x - - 23 x ^{2} + c _{1}}{6}

Solution steps

(4 x - y) d x + (6 y - x) d y = 0

Solve exact ODE:

y = \frac{x + - 23 x ^{2} + c _{1}}{6}, y = \frac{x - - 23 x ^{2} + c _{1}}{6}

y = \frac{x + - 23 x ^{2} + c _{1}}{6}, y = \frac{x - - 23 x ^{2} + c _{1}}{6}

\int (5 x^{2} - 6)^{\frac{3}{2}} d x

\frac{d}{d x} (\frac{12}{ln ( x )})

\int \frac{8 t ^{3} - 3 t ^{2} + 8 t}{t ^{2} + 1} d t

\int - 0.09 t d t

\frac{d}{d x} (e^{- 5 x^{3} - 2 x^{2}})

What is the solution for (4x-y)dx+(6y-x)dy=0 ?
The solution for (4x-y)dx+(6y-x)dy=0 is y=(x+sqrt(-23x^2+c_{1)})/6 ,y=(x-sqrt(-23x^2+c_{1)})/6