What is the derivative of 3x-2y^4 ?

The derivative of 3x-2y^4 is 3-8y^3(dy)/(dx)

What is the first derivative of 3x-2y^4 ?

The first derivative of 3x-2y^4 is 3-8y^3(dy)/(dx)

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\frac{d}{d x} (3 x - 2 y^{4})

3 - 8 y^{3} \frac{d y}{d x}

Solution steps

\frac{d}{d x} (3 x - 2 y^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (2 y^{4})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2 y^{4}) = 8 y^{3} \frac{d y}{d x}

= 3 - 8 y^{3} \frac{d y}{d x}

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What is the derivative of 3x-2y^4 ?
The derivative of 3x-2y^4 is 3-8y^3(dy)/(dx)
What is the first derivative of 3x-2y^4 ?
The first derivative of 3x-2y^4 is 3-8y^3(dy)/(dx)