What is the derivative of 1/(sqrt(8+x^2)) ?

The derivative of 1/(sqrt(8+x^2)) is -x/((8+x^2)^{3/2)}

What is the first derivative of 1/(sqrt(8+x^2)) ?

The first derivative of 1/(sqrt(8+x^2)) is -x/((8+x^2)^{3/2)}

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\frac{d}{d x} (\frac{1}{8 + x ^{2}})

- \frac{x}{( 8 + x ^{2} ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{1}{8 + x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((8 + x^{2})^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( 8 + x ^{2} ) ^{\frac{3}{2}}} \frac{d}{d x} (8 + x^{2})

= - \frac{1}{2 ( 8 + x ^{2} ) ^{\frac{3}{2}}} \frac{d}{d x} (8 + x^{2})

\frac{d}{d x} (8 + x^{2}) = 2 x

= - \frac{1}{2 ( 8 + x ^{2} ) ^{\frac{3}{2}}} \cdot 2 x

Simplify

- \frac{1}{2 ( 8 + x ^{2} ) ^{\frac{3}{2}}} \cdot 2 x : - \frac{x}{( 8 + x ^{2} ) ^{\frac{3}{2}}}

= - \frac{x}{( 8 + x ^{2} ) ^{\frac{3}{2}}}

\int 4 x^{2} + 1 d x

\frac{3}{5 x + 2}

f (x) = 6 x + 5

\frac{\partial}{\partial x} (\frac{( 4 x - 4 y )}{4 x + 3 y})

y = (x^{3} - 9 x)^{8}, (- 3, 0)

What is the derivative of 1/(sqrt(8+x^2)) ?
The derivative of 1/(sqrt(8+x^2)) is -x/((8+x^2)^{3/2)}
What is the first derivative of 1/(sqrt(8+x^2)) ?
The first derivative of 1/(sqrt(8+x^2)) is -x/((8+x^2)^{3/2)}