What is the derivative of (sqrt(2x-3)/(x^2)) ?

The derivative of (sqrt(2x-3)/(x^2)) is (3(-x+2))/(x^3sqrt(2x-3))

What is the first derivative of (sqrt(2x-3)/(x^2)) ?

The first derivative of (sqrt(2x-3)/(x^2)) is (3(-x+2))/(x^3sqrt(2x-3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{2 x - 3}{x ^{2}})

\frac{3 ( - x + 2 )}{x ^{3} 2 x - 3}

Solution steps

\frac{d}{d x} (\frac{2 x - 3}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x - 3 ) x ^{2} - \frac{d}{d x} ( x ^{2} ) 2 x - 3}{( x ^{2} ) ^{2}}

\frac{d}{d x} (2 x - 3) = \frac{1}{2 x - 3}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{\frac{1}{2 x - 3} x ^{2} - 2 x 2 x - 3}{( x ^{2} ) ^{2}}

Simplify

\frac{\frac{1}{2 x - 3} x ^{2} - 2 x 2 x - 3}{( x ^{2} ) ^{2}} : \frac{3 ( - x + 2 )}{x ^{3} 2 x - 3}

= \frac{3 ( - x + 2 )}{x ^{3} 2 x - 3}

\int \frac{81 + x ^{2}}{x} d x

x \to \infty lim (3 x^{3} + 3 x^{2} - x)

\frac{1}{s ^{2} ( s ^{2} + 1 )}

\int \frac{6 - x}{6 + x} d x

n = 0 \sum \infty \frac{2 ^{n}}{1 ^{n}}

What is the derivative of (sqrt(2x-3)/(x^2)) ?
The derivative of (sqrt(2x-3)/(x^2)) is (3(-x+2))/(x^3sqrt(2x-3))
What is the first derivative of (sqrt(2x-3)/(x^2)) ?
The first derivative of (sqrt(2x-3)/(x^2)) is (3(-x+2))/(x^3sqrt(2x-3))