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Popular >

(4t+2y+5)dt-dy=0

Solution

(4 t + 2 y + 5) d t - d y = 0

Solution

y = - 2 t - \frac{7}{2} + c_{1} e^{2 t}

Solution steps

(4 t + 2 y + 5) d t - d y = 0

Solve linear ODE:

y = - 2 t - \frac{7}{2} + c_{1} e^{2 t}

y = - 2 t - \frac{7}{2} + c_{1} e^{2 t}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for (4t+2y+5)dt-dy=0 ?
The solution for (4t+2y+5)dt-dy=0 is y=-2t-7/2+c_{1}e^{2t}