What is the derivative of [x+(x+sin^2(x)^7]^4) ?

The derivative of [x+(x+sin^2(x)^7]^4) is 4(x+(x+sin^2(x))^7)^3(1+7(x+sin^2(x))^6(1+sin(2x)))

What is the first derivative of [x+(x+sin^2(x)^7]^4) ?

The first derivative of [x+(x+sin^2(x)^7]^4) is 4(x+(x+sin^2(x))^7)^3(1+7(x+sin^2(x))^6(1+sin(2x)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ([x + (x + sin^{2} (x))^{7}]^{4})

4 (x + (x + sin^{2} (x))^{7})^{3} (1 + 7 (x + sin^{2} (x))^{6} (1 + sin (2 x)))

Solution steps

\frac{d}{d x} ((x + (x + sin^{2} (x))^{7})^{4})

Apply the chain rule:

4 (x + (x + sin^{2} (x))^{7})^{3} \frac{d}{d x} (x + (x + sin^{2} (x))^{7})

= 4 (x + (x + sin^{2} (x))^{7})^{3} \frac{d}{d x} (x + (x + sin^{2} (x))^{7})

\frac{d}{d x} (x + (x + sin^{2} (x))^{7}) = 1 + 7 (x + sin^{2} (x))^{6} (1 + sin (2 x))

= 4 (x + (x + sin^{2} (x))^{7})^{3} (1 + 7 (x + sin^{2} (x))^{6} (1 + sin (2 x)))

\frac{\partial}{\partial x} (cos^{3} (x^{3} y^{8}))

y^{^{''}} + 5 y^{^{'}} + 6 y = 4 e^{- 2 t}

(1 + \frac{3}{y} + x) \frac{d y}{d x} + y = \frac{3}{x} - 1

arcsin (x^{2})

\int sin (4 π x) d x

What is the derivative of [x+(x+sin^2(x)^7]^4) ?
The derivative of [x+(x+sin^2(x)^7]^4) is 4(x+(x+sin^2(x))^7)^3(1+7(x+sin^2(x))^6(1+sin(2x)))
What is the first derivative of [x+(x+sin^2(x)^7]^4) ?
The first derivative of [x+(x+sin^2(x)^7]^4) is 4(x+(x+sin^2(x))^7)^3(1+7(x+sin^2(x))^6(1+sin(2x)))