What is the integral from 1 to e of ln(14x) ?

The integral from 1 to e of ln(14x) is eln(14e)-e-ln(14)+1

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integral from 1 to e of ln(14x)

\int_{1}^{e} ln (14 x) d x

e ln (14 e) - e - ln (14) + 1

Decimal Notation

5.53464 \dots

Solution steps

\int_{1}^{e} ln (14 x) d x

Apply Integration By Parts

: [x ln (14 x) - \int 1 d x]_{1}^{e}

= [x ln (14 x) - \int 1 d x]_{1}^{e}

\int 1 d x = x

= [x ln (14 x) - x]_{1}^{e}

Compute the boundaries:

e ln (14 e) - e - ln (14) + 1

= e ln (14 e) - e - ln (14) + 1

\int \frac{cos ^{4} ( x )}{sin ^{2} ( x )} d x

\frac{( s ^{2} )}{s ^{3} - 1}

\frac{\partial}{\partial x} (e^{- (x^{2} + y^{2})})

x \to 8 lim (x - 2)

\int (x + 1)^{\frac{1}{2}} x d x

What is the integral from 1 to e of ln(14x) ?
The integral from 1 to e of ln(14x) is eln(14e)-e-ln(14)+1