What is derivative of f(x)=tan^2(sin(θ)) ?

The answer to derivative of f(x)=tan^2(sin(θ)) is derivative of θ=0

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derivative of f(x)=tan^2(sin(θ))

derivative of

f (x) = tan^{2} (sin (θ))

\frac{d}{d x} (θ) = 0

Solution steps

f (x) = tan^{2} (sin (θ))

Treat

θ

θ (x)

Differentiate both sides:

0 = 2 tan (sin (θ)) sec^{2} (sin (θ)) cos (θ) \frac{d}{d x} (θ)

Isolate

\frac{d}{d x} (θ) : \frac{d}{d x} (θ) = 0

\frac{d}{d x} (θ) = 0

f (x) = 2 x^{3} - 8 x, at x = 2

x \to 0 lim (3 e^{- x})

y = x^{4} + 2 x^{2} - x

\frac{d}{d x} (\frac{1}{5 x ^{4}} - \frac{5}{2 x})

f (x) = 6 x^{2}, (2, 24)

What is derivative of f(x)=tan^2(sin(θ)) ?
The answer to derivative of f(x)=tan^2(sin(θ)) is derivative of θ=0