What is the integral from 0 to infinity of e^{-10x} ?

The integral from 0 to infinity of e^{-10x} is 1/10

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integral from 0 to infinity of e^{-10x}

\int_{0}^{\infty} e^{- 10 x} d x

\frac{1}{10}

Decimal Notation

0.1

Solution steps

\int_{0}^{\infty} e^{- 10 x} d x

Compute the indefinite integral:

\int e^{- 10 x} d x = - \frac{1}{10} e^{- 10 x} + C

Compute the boundaries:

\int_{0}^{\infty} e^{- 10 x} d x = 0 - (- \frac{1}{10})

= 0 - (- \frac{1}{10})

Simplify

= \frac{1}{10}

x \to 0 + lim (∣ x ∣)

f (t) = - 3 t^{2} + 2 t - 4

\frac{d}{d x} (ln (1 + x^{2}) - arcsin (\frac{1}{x}))

\int (12 x^{11} - \frac{11}{x ^{11}}) d x

f (x) = 1 + e^{x}

What is the integral from 0 to infinity of e^{-10x} ?
The integral from 0 to infinity of e^{-10x} is 1/10