What is the derivative of log_{4}(\sqrt[3]{x}) ?

The derivative of log_{4}(\sqrt[3]{x}) is 1/(6ln(2)\sqrt[3]{x)x^{2/3}}

What is the first derivative of log_{4}(\sqrt[3]{x}) ?

The first derivative of log_{4}(\sqrt[3]{x}) is 1/(6ln(2)\sqrt[3]{x)x^{2/3}}

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Solution steps

Apply log rule:

lo g_{a} (b) = \frac{ln ( b )}{ln ( a )}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply the chain rule:

Simplify

\int \frac{1}{x ^{4} + 4 x ^{2} + 4} d x

ln (w (h - l) + π - T) + ln (l)

\frac{\partial}{\partial x} (x^{2} + 3 x y)

y = \frac{x}{6} - \frac{6}{x}

\frac{\partial}{\partial x} (- 0.1 \cdot cos (6 \cdot x))

What is the derivative of log_{4}(\sqrt[3]{x}) ?
The derivative of log_{4}(\sqrt[3]{x}) is 1/(6ln(2)\sqrt[3]{x)x^{2/3}}
What is the first derivative of log_{4}(\sqrt[3]{x}) ?
The first derivative of log_{4}(\sqrt[3]{x}) is 1/(6ln(2)\sqrt[3]{x)x^{2/3}}