What is the derivative of f(x)=-15x^2-14x+8 ?

The derivative of f(x)=-15x^2-14x+8 is -30x-14

What is the first derivative of f(x)=-15x^2-14x+8 ?

The first derivative of f(x)=-15x^2-14x+8 is -30x-14

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derivative of

f (x) = - 15 x^{2} - 14 x + 8

- 30 x - 14

Solution steps

\frac{d}{d x} (- 15 x^{2} - 14 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (15 x^{2}) - \frac{d}{d x} (14 x) + \frac{d}{d x} (8)

\frac{d}{d x} (15 x^{2}) = 30 x

\frac{d}{d x} (14 x) = 14

\frac{d}{d x} (8) = 0

= - 30 x - 14 + 0

Simplify

= - 30 x - 14

t^{3} e^{- 0.1 t}

\int_{1}^{\infty} \frac{1}{e ^{x}} d x

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\int 8 cos (t) d t

\frac{d y}{d x} = \frac{y}{1 + x}

What is the derivative of f(x)=-15x^2-14x+8 ?
The derivative of f(x)=-15x^2-14x+8 is -30x-14
What is the first derivative of f(x)=-15x^2-14x+8 ?
The first derivative of f(x)=-15x^2-14x+8 is -30x-14