What is the derivative of (e^x(x-2)/(x^3)) ?

The derivative of (e^x(x-2)/(x^3)) is (e^x(x^2-4x+6))/(x^4)

What is the first derivative of (e^x(x-2)/(x^3)) ?

The first derivative of (e^x(x-2)/(x^3)) is (e^x(x^2-4x+6))/(x^4)

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\frac{d}{d x} (\frac{e ^{x} ( x - 2 )}{x ^{3}})

\frac{e ^{x} ( x ^{2} - 4 x + 6 )}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{e ^{x} ( x - 2 )}{x ^{3}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( e ^{x} ( x - 2 ) ) x ^{3} - \frac{d}{d x} ( x ^{3} ) e ^{x} ( x - 2 )}{( x ^{3} ) ^{2}}

\frac{d}{d x} (e^{x} (x - 2)) = e^{x} x - e^{x}

\frac{d}{d x} (x^{3}) = 3 x^{2}

= \frac{( e ^{x} x - e ^{x} ) x ^{3} - 3 x ^{2} e ^{x} ( x - 2 )}{( x ^{3} ) ^{2}}

Simplify

\frac{( e ^{x} x - e ^{x} ) x ^{3} - 3 x ^{2} e ^{x} ( x - 2 )}{( x ^{3} ) ^{2}} : \frac{e ^{x} ( x ^{2} - 4 x + 6 )}{x ^{4}}

= \frac{e ^{x} ( x ^{2} - 4 x + 6 )}{x ^{4}}

f (x) = \frac{3}{4 x + 1}

x \to 1 - lim (- \frac{1}{x - 1})

\frac{\partial}{\partial x} (x^{3} - 6 x y + 8 y^{3})

n = 1 \sum \infty \frac{n ^{0}}{4 ^{n}}

x \to 7 lim (6 (7) - 2)

What is the derivative of (e^x(x-2)/(x^3)) ?
The derivative of (e^x(x-2)/(x^3)) is (e^x(x^2-4x+6))/(x^4)
What is the first derivative of (e^x(x-2)/(x^3)) ?
The first derivative of (e^x(x-2)/(x^3)) is (e^x(x^2-4x+6))/(x^4)