What is the integral of (9/(sqrt(x))) ?

The integral of (9/(sqrt(x))) is 18sqrt(x)+C

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integral of (9/(sqrt(x)))

\int (\frac{9}{x}) d x

18 x + C

Solution steps

\int \frac{9}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 9 \cdot 2 x^{\frac{1}{2}}

Simplify

9 \cdot 2 x^{\frac{1}{2}} : 18 x

= 18 x

Add a constant to the solution

= 18 x + C

arccsc (- 9 t^{2})

\int \frac{x + 7}{x ^{2} + 9} d x

\int \frac{1}{v ^{2}} d v

\frac{d}{d x} (sec^{n} (x))

x \to 3 lim (x - 3)

What is the integral of (9/(sqrt(x))) ?
The integral of (9/(sqrt(x))) is 18sqrt(x)+C