derivative of ln(10x^2-8)

Lösung

\frac{d}{d x} (ln (10 x^{2} - 8))

\frac{10 x}{5 x ^{2} - 4}

Schritte zur Lösung

\frac{d}{d x} (ln (10 x^{2} - 8))

Wende die Kettenregel an:

\frac{1}{10 x ^{2} - 8} \frac{d}{d x} (10 x^{2} - 8)

= \frac{1}{10 x ^{2} - 8} \frac{d}{d x} (10 x^{2} - 8)

\frac{d}{d x} (10 x^{2} - 8) = 20 x

= \frac{1}{10 x ^{2} - 8} \cdot 20 x

Vereinfache

\frac{1}{10 x ^{2} - 8} \cdot 20 x : \frac{10 x}{5 x ^{2} - 4}

= \frac{10 x}{5 x ^{2} - 4}

y^{^{'}} = e^{2 t + y - 1} - 2

\frac{\partial}{\partial x} (e^{x y} + ln (\frac{x}{y}))

\frac{\partial}{\partial x} (2 x y^{2} + 4)

w \to \infty lim (\frac{2 w ^{2} - 3 w + 4}{5 w ^{2} + 7 w - 1})

y^{^{''}} - k y = 0