What is the derivative of (ln(x+4)^2) ?

The derivative of (ln(x+4)^2) is (2ln(x+4))/(x+4)

What is the first derivative of (ln(x+4)^2) ?

The first derivative of (ln(x+4)^2) is (2ln(x+4))/(x+4)

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\frac{d}{d x} ((ln (x + 4))^{2})

\frac{2 ln ( x + 4 )}{x + 4}

Solution steps

\frac{d}{d x} ((ln (x + 4))^{2})

Apply the chain rule:

2 ln (x + 4) \frac{d}{d x} (ln (x + 4))

= 2 ln (x + 4) \frac{d}{d x} (ln (x + 4))

\frac{d}{d x} (ln (x + 4)) = \frac{1}{x + 4}

= 2 ln (x + 4) \frac{1}{x + 4}

Simplify

2 ln (x + 4) \frac{1}{x + 4} : \frac{2 ln ( x + 4 )}{x + 4}

= \frac{2 ln ( x + 4 )}{x + 4}

f (t) = 4 e^{t}

\frac{d}{d t} (3 t^{2})

x \to 0 - lim (\frac{x ^{2}}{6} - \frac{7}{x})

x \to \infty lim (3 \cdot x^{3})

\int x^{2} 3 - x d x

What is the derivative of (ln(x+4)^2) ?
The derivative of (ln(x+4)^2) is (2ln(x+4))/(x+4)
What is the first derivative of (ln(x+4)^2) ?
The first derivative of (ln(x+4)^2) is (2ln(x+4))/(x+4)