What is (\partial}{\partial x}(\frac{(2pi*l))/x) ?

The answer to (\partial}{\partial x}(\frac{(2pi*l))/x) is -(2pil)/(x^2)

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(\partial}{\partial x}(\frac{(2pi*l))/x)

\frac{\partial}{\partial x} (\frac{( 2 π \cdot l )}{x})

- \frac{2 π l}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{( 2 π l )}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 π l \frac{\partial}{\partial x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 π l \frac{\partial}{\partial x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 π l (- 1 \cdot x^{- 1 - 1})

Simplify

2 π l (- 1 \cdot x^{- 1 - 1}) : - \frac{2 π l}{x ^{2}}

= - \frac{2 π l}{x ^{2}}

\int x^{3} + 2 x^{2} - 1 d x

y^{^{'}} = (5 x + \frac{7}{x}) (7 x^{2} - 6)

(- 2.4) (9.4)

x \to 0 lim (\frac{1 - 1}{x})

\int \frac{7}{x ( x ^{2} + 1 )} d x

What is (\partial}{\partial x}(\frac{(2pi*l))/x) ?
The answer to (\partial}{\partial x}(\frac{(2pi*l))/x) is -(2pil)/(x^2)