What is the derivative of f(x)=x^3+3x^2-2x+1 ?

The derivative of f(x)=x^3+3x^2-2x+1 is 3x^2+6x-2

What is the first derivative of f(x)=x^3+3x^2-2x+1 ?

The first derivative of f(x)=x^3+3x^2-2x+1 is 3x^2+6x-2

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derivative of

f (x) = x^{3} + 3 x^{2} - 2 x + 1

3 x^{2} + 6 x - 2

Solution steps

\frac{d}{d x} (x^{3} + 3 x^{2} - 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 3 x^{2} + 6 x - 2 + 0

Simplify

= 3 x^{2} + 6 x - 2

\frac{d}{d x} (e^{x} x - e^{x})

\frac{\partial}{\partial y} (x^{2} z)

\int (9 - t^{2}) e^{t^{2}} d t

\int_{0}^{1} t^{5} e^{t} d t

What is the derivative of f(x)=x^3+3x^2-2x+1 ?
The derivative of f(x)=x^3+3x^2-2x+1 is 3x^2+6x-2
What is the first derivative of f(x)=x^3+3x^2-2x+1 ?
The first derivative of f(x)=x^3+3x^2-2x+1 is 3x^2+6x-2