What is (\partial)/(\partial y)(3x^3y^2) ?

The answer to (\partial)/(\partial y)(3x^3y^2) is 6x^3y

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(\partial)/(\partial y)(3x^3y^2)

\frac{\partial}{\partial y} (3 x^{3} y^{2})

6 x^{3} y

Solution steps

\frac{\partial}{\partial y} (3 x^{3} y^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 x^{3} \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 x^{3} \cdot 2 y^{2 - 1}

Simplify

= 6 x^{3} y

\frac{d}{d x} (x (1 - x))

\frac{d}{d t} (sin (t^{2}))

\int e^{- x} x d x

\frac{\partial}{\partial x} (4 x^{2} y^{3} + 4)

\int \frac{1}{4 - e ^{2 x}} d x

What is (\partial)/(\partial y)(3x^3y^2) ?
The answer to (\partial)/(\partial y)(3x^3y^2) is 6x^3y