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Popular >

3y^{''}+27y=0

Solution

3 y^{^{''}} + 27 y = 0

Solution

y = c_{1} cos (3 t) + c_{2} sin (3 t)

Solution steps

3 y^{''} (t) + 27 y = 0

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t)

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Frequently Asked Questions (FAQ)

What is the solution for 3y^{''}+27y=0 ?
The solution for 3y^{''}+27y=0 is y=c_{1}cos(3t)+c_{2}sin(3t)