What is the tangent of y=sqrt(x+5),(4,3) ?

The tangent of y=sqrt(x+5),(4,3) is y= 1/6 x+7/3

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tangent of y=sqrt(x+5),(4,3)

tangent of

y = x + 5, (4, 3)

y = \frac{1}{6} x + \frac{7}{3}

Solution steps

Find the slope of

y = x + 5 : \frac{d y}{d x} = \frac{1}{2 x + 5}

Compute the slope of

y = x + 5

(4, 3) : m = \frac{1}{6}

Find the line with slope m=

\frac{1}{6}

and passing through

(4, 3) : y = \frac{1}{6} x + \frac{7}{3}

y = \frac{1}{6} x + \frac{7}{3}

\int (- \frac{2000}{x ^{2}}) d x

\int (3 x^{2} + 2 x) \cdot ln (x) d x

x \to - 8 lim (\frac{8 - x}{8 + x})

n = 1 \sum \infty \frac{n ^{2}}{2 ^{n}}

\frac{d}{d y} (- cos (y))

What is the tangent of y=sqrt(x+5),(4,3) ?
The tangent of y=sqrt(x+5),(4,3) is y= 1/6 x+7/3