What is the solution for 5x-8ysqrt(x^2+1)(dy)/(dx)=0,y(0)=3 ?

The solution for 5x-8ysqrt(x^2+1)(dy)/(dx)=0,y(0)=3 is y=(sqrt(5\sqrt{x^2+1)+31})/2

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5x-8ysqrt(x^2+1)(dy)/(dx)=0,y(0)=3

5 x - 8 y x^{2} + 1 \frac{d y}{d x} = 0, y (0) = 3

y = \frac{5 x ^{2} + 1 + 31}{2}

Solution steps

5 x - 8 y x^{2} + 1 \frac{d y}{d x} = 0

Solve separable ODE:

y = \frac{5 x ^{2} + 1 + 31}{2}

y = \frac{5 x ^{2} + 1 + 31}{2}

\frac{d}{d x} (e^{2 x s i n (2 x)})

y^{^{''}} - 2 y^{^{'}} + 5 y = 0

x \to 0 + lim (cos (x) ln (x))

x \to 0 lim (\frac{sin ( x ) - x}{x sin ( x )})

\frac{\partial}{\partial y} (e^{x^{2} + y^{2}} \cdot 2 x)

What is the solution for 5x-8ysqrt(x^2+1)(dy)/(dx)=0,y(0)=3 ?
The solution for 5x-8ysqrt(x^2+1)(dy)/(dx)=0,y(0)=3 is y=(sqrt(5\sqrt{x^2+1)+31})/2