What is the solution for derivative of y^4= derivative of 4x ?

The solution for derivative of y^4= derivative of 4x is y=\sqrt[4]{4x+c_{1}},y=-\sqrt[4]{4x+c_{1}}

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derivative of y^4= derivative of 4x

\frac{d}{d x} y^{4} = \frac{d}{d x} (4 x)

Solution steps

\frac{d}{d x} (y^{4}) = \frac{d}{d x} (4 x)

Solve separable ODE:

x, 11, \frac{1}{44} x^{2}

\int 2 \frac{y}{5} d y

\int \frac{x}{9 - x ^{4}} d x

y^{^{''}} + 2 y^{^{'}} + 5 y = 0, y (0) = 2, y^{^{'}} (0) = - 1

n \to \infty lim (\frac{1}{x ^{n - 1}})

What is the solution for derivative of y^4= derivative of 4x ?
The solution for derivative of y^4= derivative of 4x is y=\sqrt[4]{4x+c_{1}},y=-\sqrt[4]{4x+c_{1}}