What is the integral from 1 to 2 of x^3+1/(4x^3) ?

The integral from 1 to 2 of x^3+1/(4x^3) is 123/32

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integral from 1 to 2 of x^3+1/(4x^3)

\int_{1}^{2} x^{3} + \frac{1}{4 x ^{3}} d x

\frac{123}{32}

Decimal Notation

3.84375

Solution steps

\int_{1}^{2} x^{3} + \frac{1}{4 x ^{3}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{3} d x + \int_{1}^{2} \frac{1}{4 x ^{3}} d x

\int_{1}^{2} x^{3} d x = \frac{15}{4}

\int_{1}^{2} \frac{1}{4 x ^{3}} d x = \frac{3}{32}

= \frac{15}{4} + \frac{3}{32}

Simplify

\frac{15}{4} + \frac{3}{32} : \frac{123}{32}

= \frac{123}{32}

x \to \infty lim (- 7)

cos (x) - tan (x)

\frac{d y}{d x} = - y^{2}

x \to - 2 lim (x^{3} - 2 x^{2} + 4 x + 8)

x \to 0 + lim (\frac{5}{2 x ^{4}})

What is the integral from 1 to 2 of x^3+1/(4x^3) ?
The integral from 1 to 2 of x^3+1/(4x^3) is 123/32