What is the integral from 1 to e of ln(9x) ?

The integral from 1 to e of ln(9x) is eln(9e)-e-2ln(3)+1

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integral from 1 to e of ln(9x)

\int_{1}^{e} ln (9 x) d x

e ln (9 e) - e - 2 ln (3) + 1

Decimal Notation

4.77545 \dots

Solution steps

\int_{1}^{e} ln (9 x) d x

Apply Integration By Parts

: [x ln (9 x) - \int 1 d x]_{1}^{e}

= [x ln (9 x) - \int 1 d x]_{1}^{e}

\int 1 d x = x

= [x ln (9 x) - x]_{1}^{e}

Compute the boundaries:

e ln (9 e) - e - 2 ln (3) + 1

= e ln (9 e) - e - 2 ln (3) + 1

\frac{\partial}{\partial x} (x^{5} e^{x y} + 3 x)

\frac{3}{8 x ^{\frac{5}{2}}}

\frac{d}{d x} (4 x y^{3})

x (9.3)

y^{^{'}} = - \frac{y}{t} + 2

What is the integral from 1 to e of ln(9x) ?
The integral from 1 to e of ln(9x) is eln(9e)-e-2ln(3)+1