What is the tangent of y=sin(3x)+sin^2(3x),(0,0) ?

The tangent of y=sin(3x)+sin^2(3x),(0,0) is y=3x

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tangent of y=sin(3x)+sin^2(3x),(0,0)

tangent of

y = sin (3 x) + sin^{2} (3 x), (0, 0)

y = 3 x

Solution steps

Find the slope of

y = sin (3 x) + sin^{2} (3 x) : \frac{d y}{d x} = cos (3 x) \cdot 3 + 3 sin (6 x)

Compute the slope of

y = sin (3 x) + sin^{2} (3 x)

(0, 0) : m = 3

Find the line with slope m=

3

and passing through

(0, 0) : y = 3 x

y = 3 x

x \to \infty lim (2, x)

\frac{\partial}{\partial x} (6 x^{2} + 9 x y + 5 y^{2})

((1 + sin (x))^{2} + (1 + cos (x))^{4})^{^{'}}

\int (x + 1) 2 d x

y^{^{'}} - 4 y = 2 x y^{2}

What is the tangent of y=sin(3x)+sin^2(3x),(0,0) ?
The tangent of y=sin(3x)+sin^2(3x),(0,0) is y=3x