What is the derivative of (3x+2y^5) ?

The derivative of (3x+2y^5) is 5(3x+2y)^4(3+2(dy)/(dx))

What is the first derivative of (3x+2y^5) ?

The first derivative of (3x+2y^5) is 5(3x+2y)^4(3+2(dy)/(dx))

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\frac{d}{d x} ((3 x + 2 y)^{5})

5 (3 x + 2 y)^{4} (3 + 2 \frac{d y}{d x})

Solution steps

\frac{d}{d x} ((3 x + 2 y)^{5})

Apply the chain rule:

5 (3 x + 2 y)^{4} \frac{d}{d x} (3 x + 2 y)

= 5 (3 x + 2 y)^{4} \frac{d}{d x} (3 x + 2 y)

\frac{d}{d x} (3 x + 2 y) = 3 + 2 \frac{d y}{d x}

= 5 (3 x + 2 y)^{4} (3 + 2 \frac{d y}{d x})

\int_{0}^{4} \frac{5}{2 x + 1} d x

3^{t}

x \cdot cos (2 x)

lo g_{5} (x^{2} - 1)

y = (2)^{x}

What is the derivative of (3x+2y^5) ?
The derivative of (3x+2y^5) is 5(3x+2y)^4(3+2(dy)/(dx))
What is the first derivative of (3x+2y^5) ?
The first derivative of (3x+2y^5) is 5(3x+2y)^4(3+2(dy)/(dx))