What is integral from 2 to 6 of f(x) ?

The answer to integral from 2 to 6 of f(x) is f*16

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integral from 2 to 6 of f(x)

\int_{2}^{6} f (x) d x

f \cdot 16

Solution steps

\int_{2}^{6} f x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{2}^{6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{2}^{6}

= f [\frac{x ^{2}}{2}]_{2}^{6}

Compute the boundaries:

16

= f \cdot 16

(2, 3), (4, 8)

y^{^{''}} + 9 y = 0, y (0) = 8, y^{^{'}} (0) = 7

\frac{\frac{1}{500}}{140 + 8 s + s ^{2}}

\int (2 x - \frac{1}{2 x}) d x

y^{^{''}} + 6.2832 y = 10

What is integral from 2 to 6 of f(x) ?
The answer to integral from 2 to 6 of f(x) is f*16