What is the derivative of y=x^2(x+3) ?

The derivative of y=x^2(x+3) is 3x^2+6x

What is the first derivative of y=x^2(x+3) ?

The first derivative of y=x^2(x+3) is 3x^2+6x

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derivative of

y = x^{2} (x + 3)

3 x^{2} + 6 x

Solution steps

\frac{d}{d x} (x^{2} (x + 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = x + 3

= \frac{d}{d x} (x^{2}) (x + 3) + \frac{d}{d x} (x + 3) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x + 3) = 1

= 2 x (x + 3) + 1 \cdot x^{2}

Simplify

2 x (x + 3) + 1 \cdot x^{2} : 3 x^{2} + 6 x

= 3 x^{2} + 6 x

x \to \infty lim (1.9)

\frac{0.001 s}{s ^{2} + 4}

\int \frac{13 x - 6}{x ( 3 x - 2 )} d x

n = 1 \sum \infty \frac{( 1 ^{n} )}{n}

\frac{d}{d x} ((2 x) d x)

What is the derivative of y=x^2(x+3) ?
The derivative of y=x^2(x+3) is 3x^2+6x
What is the first derivative of y=x^2(x+3) ?
The first derivative of y=x^2(x+3) is 3x^2+6x