What is the derivative of-sin(2t) ?

The derivative of-sin(2t) is -cos(2t)*2

What is the first derivative of-sin(2t) ?

The first derivative of-sin(2t) is -cos(2t)*2

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derivative of

- sin (2 t)

- cos (2 t) \cdot 2

Solution steps

\frac{d}{d t} (- sin (2 t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d t} (sin (2 t))

Apply the chain rule:

cos (2 t) \frac{d}{d t} (2 t)

= cos (2 t) \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = 2

= - cos (2 t) \cdot 2

y = arctan (4 t)

x \to 2 - lim (2 - x^{2})

x^{2} \frac{d y}{d x} = 2 y

(\frac{g ( t )}{f ( t )})^{'}

ln (1 - x^{2})

What is the derivative of-sin(2t) ?
The derivative of-sin(2t) is -cos(2t)*2
What is the first derivative of-sin(2t) ?
The first derivative of-sin(2t) is -cos(2t)*2