What is the limit as x approaches 0+of 2x^{sqrt(x)} ?

The limit as x approaches 0+of 2x^{sqrt(x)} is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of 2x^{sqrt(x)}

x \to 0 + lim (2 x^{x})

2

Solution steps

x \to 0 + lim (2 x^{x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 2 \cdot x \to 0 + lim (x^{x})

Apply exponent rules

= 2 \cdot x \to 0 + lim (e^{x l n (x)})

Apply the Limit Chain Rule:

1

= 2 \cdot 1

Simplify

= 2

\int (ln (x + 1 + x^{2})) d x

\frac{\partial}{\partial x} (x \cdot e^{y})

x \to \infty lim (9 x^{2} - 1)

y = \frac{4}{3} x^{3} - 5 x + 4

\frac{d}{d x} (4 x 3 x^{4})

What is the limit as x approaches 0+of 2x^{sqrt(x)} ?
The limit as x approaches 0+of 2x^{sqrt(x)} is 2