What is the derivative of 4sin^2(2x) ?

The derivative of 4sin^2(2x) is 8sin(4x)

What is the first derivative of 4sin^2(2x) ?

The first derivative of 4sin^2(2x) is 8sin(4x)

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\frac{d}{d x} (4 sin^{2} (2 x))

8 sin (4 x)

Solution steps

\frac{d}{d x} (4 sin^{2} (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (sin^{2} (2 x))

Apply the chain rule:

2 sin (2 x) \frac{d}{d x} (sin (2 x))

= 2 sin (2 x) \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= 4 \cdot 2 sin (2 x) cos (2 x) \cdot 2

Simplify

4 \cdot 2 sin (2 x) cos (2 x) \cdot 2 : 8 sin (4 x)

= 8 sin (4 x)

\frac{\partial}{\partial y} (4 x^{3} y^{3} - 4)

y^{^{''}} - 2 y^{^{'}} - 4 y = 0

x \to 2 lim (6 x^{3} + 1)

\frac{d}{d t} (1 - t)

\frac{\partial}{\partial x} (2 - x^{4} + 2 x^{2} - y^{2})

What is the derivative of 4sin^2(2x) ?
The derivative of 4sin^2(2x) is 8sin(4x)
What is the first derivative of 4sin^2(2x) ?
The first derivative of 4sin^2(2x) is 8sin(4x)