What is the integral of 7x^{3/2} ?

The integral of 7x^{3/2} is 14/5 x^{5/2}+C

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integral of 7x^{3/2}

\int 7 x^{\frac{3}{2}} d x

\frac{14}{5} x^{\frac{5}{2}} + C

Solution steps

\int 7 x^{\frac{3}{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int x^{\frac{3}{2}} d x

Apply the Power Rule

: \frac{2}{5} x^{\frac{5}{2}}

= 7 \cdot \frac{2}{5} x^{\frac{5}{2}}

Simplify

7 \cdot \frac{2}{5} x^{\frac{5}{2}} : \frac{14}{5} x^{\frac{5}{2}}

= \frac{14}{5} x^{\frac{5}{2}}

Add a constant to the solution

= \frac{14}{5} x^{\frac{5}{2}} + C

y = \frac{3 x - 7}{2 x + 4}

sin^{2} (3 t)

\frac{\partial}{\partial x} (2 x^{3} + 6 x y - 2 y^{4})

\frac{x ^{2} + 1}{2 x - 3}

x^{2} = \frac{4 x + y}{4 x - y}