What is the integral of (4x^7-3cos(x)) ?

The integral of (4x^7-3cos(x)) is (x^8)/2-3sin(x)+C

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integral of (4x^7-3cos(x))

\int (4 x^{7} - 3 cos (x)) d x

\frac{x ^{8}}{2} - 3 sin (x) + C

Solution steps

\int 4 x^{7} - 3 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{7} d x - \int 3 cos (x) d x

\int 4 x^{7} d x = \frac{x ^{8}}{2}

\int 3 cos (x) d x = 3 sin (x)

= \frac{x ^{8}}{2} - 3 sin (x)

Add a constant to the solution

= \frac{x ^{8}}{2} - 3 sin (x) + C

f (x) = 4 x + 8

y^{^{'}} = - x - y

x \to 1 + lim (4 x - 1)

x \to \infty lim (3 e^{x})

n = 0 \sum \infty e^{\frac{- 9 n}{2}}

What is the integral of (4x^7-3cos(x)) ?
The integral of (4x^7-3cos(x)) is (x^8)/2-3sin(x)+C