What is the limit as x approaches 1 of 4x-4/(x-1) ?

The limit as x approaches 1 of 4x-4/(x-1) is diverges

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limit as x approaches 1 of 4x-4/(x-1)

x \to 1 lim (4 x - \frac{4}{x - 1})

diverges

Solution steps

x \to 1 lim (4 x - \frac{4}{x - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (4 x - \frac{4}{x - 1}) = - \infty

x \to 1 - lim (4 x - \frac{4}{x - 1}) = \infty

= diverges

\int x^{p} ln (x) d x

f (x) = (x^{2} + 9)^{\frac{1}{2}}

5^{y}

\int (r^{3} + 1)^{2} r^{2} d r

\frac{1 - ln ( x )}{x ^{2}}

What is the limit as x approaches 1 of 4x-4/(x-1) ?
The limit as x approaches 1 of 4x-4/(x-1) is diverges