What is the derivative of 2tan(x+tan^2(x)) ?

The derivative of 2tan(x+tan^2(x)) is 2sec^2(x)+2tan(x)sec^2(x)

What is the first derivative of 2tan(x+tan^2(x)) ?

The first derivative of 2tan(x+tan^2(x)) is 2sec^2(x)+2tan(x)sec^2(x)

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\frac{d}{d x} (2 tan (x) + tan^{2} (x))

2 sec^{2} (x) + 2 tan (x) sec^{2} (x)

Solution steps

\frac{d}{d x} (2 tan (x) + tan^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 tan (x)) + \frac{d}{d x} (tan^{2} (x))

\frac{d}{d x} (2 tan (x)) = 2 sec^{2} (x)

\frac{d}{d x} (tan^{2} (x)) = 2 tan (x) sec^{2} (x)

= 2 sec^{2} (x) + 2 tan (x) sec^{2} (x)

\int e^{- 10 x^{2}} d x

\int_{- 1}^{2} x^{2} d x

3 tan (θ)

y^{^{'}} + y = x y^{2}, y (0) = \frac{1}{2}

\int - \frac{sin ( ln ( x ) ) sin ( 2 ln ( x ) )}{2 x} d x

What is the derivative of 2tan(x+tan^2(x)) ?
The derivative of 2tan(x+tan^2(x)) is 2sec^2(x)+2tan(x)sec^2(x)
What is the first derivative of 2tan(x+tan^2(x)) ?
The first derivative of 2tan(x+tan^2(x)) is 2sec^2(x)+2tan(x)sec^2(x)