What is the solution for y^'+3y=2-3e^{-x} ?

The solution for y^'+3y=2-3e^{-x} is y= 2/3-3/(2e^x)+(c_{1})/(e^{3x)}

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y^'+3y=2-3e^{-x}

y^{^{'}} + 3 y = 2 - 3 e^{- x}

y = \frac{2}{3} - \frac{3}{2 e ^{x}} + \frac{c _{1}}{e ^{3 x}}

Solution steps

y^{'} (x) + 3 y = 2 - 3 e^{- x}

Solve linear ODE:

y = \frac{2}{3} - \frac{3}{2 e ^{x}} + \frac{c _{1}}{e ^{3 x}}

y = \frac{2}{3} - \frac{3}{2 e ^{x}} + \frac{c _{1}}{e ^{3 x}}

x \to 69 lim (\frac{x - 69}{x - 69})

\int \frac{34}{34 + e ^{x}} d x

\int_{1}^{2} (x - 1) ln (x) d x

\frac{d}{d x} (\frac{- 2}{x - 5} - 3)

\frac{d}{d x} (\frac{1}{12 x ^{2}})

What is the solution for y^'+3y=2-3e^{-x} ?
The solution for y^'+3y=2-3e^{-x} is y= 2/3-3/(2e^x)+(c_{1})/(e^{3x)}