What is the solution for (dy)/(dt)+2y=1,y(0)= 5/2 ?

The solution for (dy)/(dt)+2y=1,y(0)= 5/2 is y= 1/2+2/(e^{2t)}

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(dy)/(dt)+2y=1,y(0)= 5/2

\frac{d y}{d t} + 2 y = 1, y (0) = \frac{5}{2}

y = \frac{1}{2} + \frac{2}{e ^{2 t}}

Solution steps

\frac{d y}{d t} + 2 y = 1

Solve linear ODE:

y = \frac{1}{2} + \frac{2}{e ^{2 t}}

y = \frac{1}{2} + \frac{2}{e ^{2 t}}

\frac{\partial}{\partial z} (x y - 3 x z + yz)

\frac{d ^{3}}{d x ^{3}} (x^{4} - 3 x^{2} + 6 x - 5)

\int - 2 e^{- \frac{x}{2}} d x

\frac{d}{d x} (arctan (\frac{1 - x}{1 + x}))

x^{- 2}, 3

What is the solution for (dy)/(dt)+2y=1,y(0)= 5/2 ?
The solution for (dy)/(dt)+2y=1,y(0)= 5/2 is y= 1/2+2/(e^{2t)}