What is the derivative of f(x)=x^3-4x ?

The derivative of f(x)=x^3-4x is 3x^2-4

What is the first derivative of f(x)=x^3-4x ?

The first derivative of f(x)=x^3-4x is 3x^2-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = x^{3} - 4 x

3 x^{2} - 4

Solution steps

\frac{d}{d x} (x^{3} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (4 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (4 x) = 4

= 3 x^{2} - 4

\int (tan (x) sec^{2} (y)) d x

\frac{d}{d x} ((a + b x)^{3})

x \to 2 lim (x^{2} - 4 x + 1)

\int \frac{1}{( 1 + x ^{4} )} d x

\int \frac{x ^{4}}{( 7 + x ^{5} ) ^{2}} d x

What is the derivative of f(x)=x^3-4x ?
The derivative of f(x)=x^3-4x is 3x^2-4
What is the first derivative of f(x)=x^3-4x ?
The first derivative of f(x)=x^3-4x is 3x^2-4