What is the sum from n=0 to infinity of 6^n ?

The sum from n=0 to infinity of 6^n is diverges

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sum from n=0 to infinity of 6^n

n = 0 \sum \infty 6^{n}

diverges

Solution steps

n = 0 \sum \infty 6^{n}

Apply Series Geometric Test:

diverges

= diverges

\int \frac{x ^{3} - 1}{x ^{2}} d x

\frac{d}{d x} (\frac{15}{ln ( x )})

\int \frac{x ^{2}}{9 - 16 x ^{2}} d x

\frac{d}{d y} (y - x^{3})

\frac{d}{d x} (ln (x + 2) - x + 2)

What is the sum from n=0 to infinity of 6^n ?
The sum from n=0 to infinity of 6^n is diverges