What is the solution for x^2y^{''}+10xy^'+8y=x^2 ?

The solution for x^2y^{''}+10xy^'+8y=x^2 is y=(c_{1})/x+(c_{2})/(x^8)+(x^2)/(30)

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x^2y^{''}+10xy^'+8y=x^2

x^{2} y^{^{''}} + 10 x y^{^{'}} + 8 y = x^{2}

y = \frac{c _{1}}{x} + \frac{c _{2}}{x ^{8}} + \frac{x ^{2}}{30}

Solution steps

x^{2} y^{''} (x) + 10 x y^{'} (x) + 8 y = x^{2}

Solve linear ODE:

y = \frac{c _{1}}{x} + \frac{c _{2}}{x ^{8}} + \frac{x ^{2}}{30}

y = \frac{c _{1}}{x} + \frac{c _{2}}{x ^{8}} + \frac{x ^{2}}{30}

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What is the solution for x^2y^{''}+10xy^'+8y=x^2 ?
The solution for x^2y^{''}+10xy^'+8y=x^2 is y=(c_{1})/x+(c_{2})/(x^8)+(x^2)/(30)