What is area y=3(x+1),y=4(x+1),x=6 ?

The answer to area y=3(x+1),y=4(x+1),x=6 is 49/2

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area y=3(x+1),y=4(x+1),x=6

area

y = 3 (x + 1), y = 4 (x + 1), x = 6

\frac{49}{2}

Decimal Notation

24.5

Solution steps

Apply the area formula:

\int_{- 1}^{6} ∣ x + 1 ∣ d x

Solve

\int_{- 1}^{6} ∣ x + 1 ∣ d x : \frac{49}{2}

The area is:

= \frac{49}{2}

\int \frac{- 341 x + 342}{x ^{2} + x - 2} d x

\frac{\partial}{\partial x} (3 x sin (9 x^{2} y))

x \to \infty lim ((1 + x)^{\frac{3}{x}})

\int \frac{1}{x ^{2} + 36} d x

x \to - \infty lim (\frac{x ^{2} + 2}{x ^{3} + x ^{2} - 1})

What is area y=3(x+1),y=4(x+1),x=6 ?
The answer to area y=3(x+1),y=4(x+1),x=6 is 49/2