What is the integral of 0.02e^x ?

The integral of 0.02e^x is 0.02e^x+C

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integral of 0.02e^x

\int 0.02 e^{x} d x

0.02 e^{x} + C

Solution steps

\int 0.02 e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.02 \cdot \int e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= 0.02 e^{x}

Add a constant to the solution

= 0.02 e^{x} + C

2 x y^{2} + 4 = 2 (3 - x^{2} y) y^{^{'}}, y (- 1) = 8

\frac{d}{d x} (x^{3} + 3 x^{2} - 144 x)

(- 1.4) (- 4.2)

\int \frac{1}{4 x ^{2} - 4 x + 3} d x

\frac{d}{d x} (x^{3} - \frac{1}{12 x})