What is the derivative of 1/(3x+2) ?

The derivative of 1/(3x+2) is -3/((3x+2)^2)

What is the first derivative of 1/(3x+2) ?

The first derivative of 1/(3x+2) is -3/((3x+2)^2)

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derivative of

\frac{1}{3 x + 2}

- \frac{3}{( 3 x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{3 x + 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((3 x + 2)^{- 1})

Apply the chain rule:

- \frac{1}{( 3 x + 2 ) ^{2}} \frac{d}{d x} (3 x + 2)

= - \frac{1}{( 3 x + 2 ) ^{2}} \frac{d}{d x} (3 x + 2)

\frac{d}{d x} (3 x + 2) = 3

= - \frac{1}{( 3 x + 2 ) ^{2}} \cdot 3

Simplify

- \frac{1}{( 3 x + 2 ) ^{2}} \cdot 3 : - \frac{3}{( 3 x + 2 ) ^{2}}

= - \frac{3}{( 3 x + 2 ) ^{2}}

tan (x)

\frac{d}{d x} (10 x e^{- x})

\frac{d y}{d x} = \frac{2 x ^{3}}{y ^{2}}

\frac{d y}{d t} + 2 y = e^{\frac{t}{3}}

\int 17 tan^{2} (x) sec^{3} (x) d x

What is the derivative of 1/(3x+2) ?
The derivative of 1/(3x+2) is -3/((3x+2)^2)
What is the first derivative of 1/(3x+2) ?
The first derivative of 1/(3x+2) is -3/((3x+2)^2)