What is the derivative of ln(t^3) ?

The derivative of ln(t^3) is 3/t

What is the first derivative of ln(t^3) ?

The first derivative of ln(t^3) is 3/t

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derivative of

ln (t^{3})

\frac{3}{t}

Solution steps

\frac{d}{d t} (ln (t^{3}))

Apply the chain rule:

\frac{1}{t ^{3}} \frac{d}{d t} (t^{3})

= \frac{1}{t ^{3}} \frac{d}{d t} (t^{3})

\frac{d}{d t} (t^{3}) = 3 t^{2}

= \frac{1}{t ^{3}} \cdot 3 t^{2}

Simplify

\frac{1}{t ^{3}} \cdot 3 t^{2} : \frac{3}{t}

= \frac{3}{t}

y^{^{'}} = \frac{y ^{2} + x ^{2}}{2 x y}

cos (x) y^{^{'}} + sin (x) y = 0

x^{2} + 24 x + c

\frac{d}{d x} (100 x)

\int \frac{2 x ^{3}}{x ^{2} + 1} d x

What is the derivative of ln(t^3) ?
The derivative of ln(t^3) is 3/t
What is the first derivative of ln(t^3) ?
The first derivative of ln(t^3) is 3/t