What is the slope of y=-(x+1/2)^2+7/2 ?

The slope of y=-(x+1/2)^2+7/2 is -2x-1

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slope of y=-(x+1/2)^2+7/2

slope

y = - (x + \frac{1}{2})^{2} + \frac{7}{2}

- 2 x - 1

Solution steps

y = - (x + \frac{1}{2})^{2} + \frac{7}{2}

In order to find the slope of the function, take the derivative of

- (x + \frac{1}{2})^{2} + \frac{7}{2}

\frac{d}{d x} (- (x + \frac{1}{2})^{2} + \frac{7}{2}) = - 2 x - 1

- 2 x - 1

\int 3 cos (\frac{nπ x}{3}) d x

y^{^{'}} = \frac{x ^{2}}{y ( 2 + x ^{3} )}

\frac{\partial}{\partial x} (3 e^{x} cos (y))

\frac{d}{d x} ((x - 4)^{2} x^{2})

\frac{\partial}{\partial x} (- \frac{9 x ^{2}}{x ^{2} + y ^{2}})