What is the d/(dy)(sqrt(3x+4y)) ?

The d/(dy)(sqrt(3x+4y)) is 2/(sqrt(3x+4y))

What is the first d/(dy)(sqrt(3x+4y)) ?

The first d/(dy)(sqrt(3x+4y)) is 2/(sqrt(3x+4y))

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\frac{d}{d y} (3 x + 4 y)

\frac{2}{3 x + 4 y}

Solution steps

\frac{d}{d y} (3 x + 4 y)

Treat

x

as a constant

Apply the chain rule:

\frac{1}{2 3 x + 4 y} \frac{d}{d y} (3 x + 4 y)

= \frac{1}{2 3 x + 4 y} \frac{d}{d y} (3 x + 4 y)

\frac{d}{d y} (3 x + 4 y) = 4

= \frac{1}{2 3 x + 4 y} \cdot 4

Simplify

\frac{1}{2 3 x + 4 y} \cdot 4 : \frac{2}{3 x + 4 y}

= \frac{2}{3 x + 4 y}

\frac{- ( 16 )}{( 5 ( x ^{2} + 8 x + 25 ) )}

\int \frac{2}{cos ( x )} d x

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\int x (2 x + 3) d x

(3) (0.4)

What is the d/(dy)(sqrt(3x+4y)) ?
The d/(dy)(sqrt(3x+4y)) is 2/(sqrt(3x+4y))
What is the first d/(dy)(sqrt(3x+4y)) ?
The first d/(dy)(sqrt(3x+4y)) is 2/(sqrt(3x+4y))