What is the solution for (dy)/(dx)y=3^x ?

The solution for (dy)/(dx)y=3^x is y=sqrt((2*3^x+c_{1))/(ln(3))},y=-sqrt((2*3^x+c_{1))/(ln(3))}

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(dy)/(dx)y=3^x

\frac{d y}{d x} y = 3^{x}

y = \frac{2 \cdot 3 ^{x} + c _{1}}{ln ( 3 )}, y = - \frac{2 \cdot 3 ^{x} + c _{1}}{ln ( 3 )}

Solution steps

\frac{d y}{d x} y = 3^{x}

Solve separable ODE:

y = \frac{2 \cdot 3 ^{x} + c _{1}}{ln ( 3 )}, y = - \frac{2 \cdot 3 ^{x} + c _{1}}{ln ( 3 )}

y = \frac{2 \cdot 3 ^{x} + c _{1}}{ln ( 3 )}, y = - \frac{2 \cdot 3 ^{x} + c _{1}}{ln ( 3 )}

x \to \frac{1}{4} lim (8 x^{3})

\int x (4 x + 7)^{8} d x

\frac{d}{d x} ((x^{2} + 2 x) ln (2 x))

(x - y) d x + (x - y + 1) d y = 0

x \to \infty + lim (x \cdot + \frac{1}{x})

What is the solution for (dy)/(dx)y=3^x ?
The solution for (dy)/(dx)y=3^x is y=sqrt((2*3^x+c_{1))/(ln(3))},y=-sqrt((2*3^x+c_{1))/(ln(3))}