What is the derivative of 1/4 (x^8+8) ?

The derivative of 1/4 (x^8+8) is 2x^7

What is the first derivative of 1/4 (x^8+8) ?

The first derivative of 1/4 (x^8+8) is 2x^7

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derivative of

\frac{1}{4} (x^{8} + 8)

2 x^{7}

Solution steps

\frac{d}{d x} (\frac{1}{4} (x^{8} + 8))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d x} (x^{8} + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{4} (\frac{d}{d x} (x^{8}) + \frac{d}{d x} (8))

\frac{d}{d x} (x^{8}) = 8 x^{7}

\frac{d}{d x} (8) = 0

= \frac{1}{4} (8 x^{7} + 0)

Simplify

\frac{1}{4} (8 x^{7} + 0) : 2 x^{7}

= 2 x^{7}

\frac{\partial}{\partial y} (y + 3 x y^{2} - 18)

f (s) = \frac{s}{4}

\frac{\partial}{\partial x} (x^{2} - 2 x y + 3 y^{2})

\int \frac{x}{x - 11} d x

f (x) = \frac{x ^{3} - 2 x + 5}{x ^{3}}

What is the derivative of 1/4 (x^8+8) ?
The derivative of 1/4 (x^8+8) is 2x^7
What is the first derivative of 1/4 (x^8+8) ?
The first derivative of 1/4 (x^8+8) is 2x^7