What is (\partial)/(\partial y)(40x+840-40y) ?

The answer to (\partial)/(\partial y)(40x+840-40y) is -40

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(\partial)/(\partial y)(40x+840-40y)

\frac{\partial}{\partial y} (40 x + 840 - 40 y)

- 40

Solution steps

\frac{\partial}{\partial y} (40 x + 840 - 40 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (40 x) + \frac{\partial}{\partial y} (840) - \frac{\partial}{\partial y} (40 y)

\frac{\partial}{\partial y} (40 x) = 0

\frac{\partial}{\partial y} (840) = 0

\frac{\partial}{\partial y} (40 y) = 40

= 0 + 0 - 40

Simplify

= - 40

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What is (\partial)/(\partial y)(40x+840-40y) ?
The answer to (\partial)/(\partial y)(40x+840-40y) is -40